3.1.67 \(\int \log (a+b x+c x) \, dx\) [67]

Optimal. Leaf size=25 \[ -x+\frac {(a+(b+c) x) \log (a+(b+c) x)}{b+c} \]

[Out]

-x+(a+(b+c)*x)*ln(a+(b+c)*x)/(b+c)

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Rubi [A]
time = 0.01, antiderivative size = 25, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2494, 2436, 2332} \begin {gather*} \frac {(a+x (b+c)) \log (a+x (b+c))}{b+c}-x \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Log[a + b*x + c*x],x]

[Out]

-x + ((a + (b + c)*x)*Log[a + (b + c)*x])/(b + c)

Rule 2332

Int[Log[(c_.)*(x_)^(n_.)], x_Symbol] :> Simp[x*Log[c*x^n], x] - Simp[n*x, x] /; FreeQ[{c, n}, x]

Rule 2436

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] :> Dist[1/e, Subst[Int[(a + b*Log[c*
x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, n, p}, x]

Rule 2494

Int[((a_.) + Log[(c_.)*(v_)^(n_.)]*(b_.))^(p_.)*(u_.), x_Symbol] :> Int[u*(a + b*Log[c*ExpandToSum[v, x]^n])^p
, x] /; FreeQ[{a, b, c, n, p}, x] && LinearQ[v, x] &&  !LinearMatchQ[v, x] &&  !(EqQ[n, 1] && MatchQ[c*v, (e_.
)*((f_) + (g_.)*x) /; FreeQ[{e, f, g}, x]])

Rubi steps

\begin {align*} \int \log (a+b x+c x) \, dx &=\int \log (a+(b+c) x) \, dx\\ &=\frac {\text {Subst}(\int \log (x) \, dx,x,a+(b+c) x)}{b+c}\\ &=-x+\frac {(a+(b+c) x) \log (a+(b+c) x)}{b+c}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 25, normalized size = 1.00 \begin {gather*} -x+\frac {(a+(b+c) x) \log (a+(b+c) x)}{b+c} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Log[a + b*x + c*x],x]

[Out]

-x + ((a + (b + c)*x)*Log[a + (b + c)*x])/(b + c)

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Maple [A]
time = 0.11, size = 33, normalized size = 1.32

method result size
norman \(x \ln \left (b x +c x +a \right )+\frac {a \ln \left (b x +c x +a \right )}{b +c}-x\) \(32\)
derivativedivides \(\frac {\left (a +\left (b +c \right ) x \right ) \ln \left (a +\left (b +c \right ) x \right )-a -\left (b +c \right ) x}{b +c}\) \(33\)
default \(\frac {\left (a +\left (b +c \right ) x \right ) \ln \left (a +\left (b +c \right ) x \right )-a -\left (b +c \right ) x}{b +c}\) \(33\)
risch \(x \ln \left (b x +c x +a \right )+\frac {a \ln \left (a +\left (b +c \right ) x \right )}{b +c}-\frac {b x}{b +c}-\frac {c x}{b +c}\) \(46\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(ln(b*x+c*x+a),x,method=_RETURNVERBOSE)

[Out]

1/(b+c)*((a+(b+c)*x)*ln(a+(b+c)*x)-a-(b+c)*x)

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Maxima [A]
time = 0.28, size = 34, normalized size = 1.36 \begin {gather*} -\frac {b x + c x - {\left (b x + c x + a\right )} \log \left (b x + c x + a\right ) + a}{b + c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(b*x+c*x+a),x, algorithm="maxima")

[Out]

-(b*x + c*x - (b*x + c*x + a)*log(b*x + c*x + a) + a)/(b + c)

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Fricas [A]
time = 0.32, size = 30, normalized size = 1.20 \begin {gather*} -\frac {{\left (b + c\right )} x - {\left ({\left (b + c\right )} x + a\right )} \log \left ({\left (b + c\right )} x + a\right )}{b + c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(b*x+c*x+a),x, algorithm="fricas")

[Out]

-((b + c)*x - ((b + c)*x + a)*log((b + c)*x + a))/(b + c)

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Sympy [A]
time = 0.09, size = 36, normalized size = 1.44 \begin {gather*} x \log {\left (a + b x + c x \right )} + \left (- b - c\right ) \left (- \frac {a \log {\left (a + x \left (b + c\right ) \right )}}{\left (b + c\right )^{2}} + \frac {x}{b + c}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(ln(b*x+c*x+a),x)

[Out]

x*log(a + b*x + c*x) + (-b - c)*(-a*log(a + x*(b + c))/(b + c)**2 + x/(b + c))

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Giac [A]
time = 5.78, size = 34, normalized size = 1.36 \begin {gather*} -\frac {b x + c x - {\left (b x + c x + a\right )} \log \left (b x + c x + a\right ) + a}{b + c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(b*x+c*x+a),x, algorithm="giac")

[Out]

-(b*x + c*x - (b*x + c*x + a)*log(b*x + c*x + a) + a)/(b + c)

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Mupad [B]
time = 0.08, size = 31, normalized size = 1.24 \begin {gather*} x\,\ln \left (a+b\,x+c\,x\right )-x+\frac {a\,\ln \left (a+b\,x+c\,x\right )}{b+c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(log(a + b*x + c*x),x)

[Out]

x*log(a + b*x + c*x) - x + (a*log(a + b*x + c*x))/(b + c)

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